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It has the following properties 1) The graph of f is symmetrical with respect to the yaxis 2) The graph of f has a vertical asymptote at x=2 3) The graph of f passes Calculus Find an equation of the tangent line to the graph of the function f through the point (x0, y0) not on the graphIt is a straight line joining the points (0, 1), (1, 3), and (1,5) It is a straight line joining the points (4, 3), (1,2), and (4,5) It is a curve joining the points (4, 1), (2, 3), and (4,1) It is a curve joining the points (0, 1), (1, 3), and (1,5MATH 04 Homework Solution HanBom Moon Homework 3 Model Solution Section 126 ˘131 1263Describe and sketch the surface x2 z2 = 1 If we cut the surface by a plane y= kwhich is parallel to xzplane, the intersec

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Y=x^2-4x-5 graph-The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}4xy5=0 x 2 4 x − y − 5 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 4 for b, and 5y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a}1 To obtain the graph of y = (x 8)2, shift the graph of y = x2 2 To obtain the graph of y = x2 6, shift the graph of y = x2 A ball is thrown straight up from a height of 3 ft with a speed of 32 ft/s Its height above the ground after x seconds is given by the quadratic function y = 16x2 32x 3




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Select three options The domain is {xx ≤ 2} The range is {yy ≤ 6} The function is increasing over the interval (∞ , 2) The function is decreasing over the interval (−4, ∞) The function has a positive yinterceptLet's graph y=x 2 (blue), y=¼x 2 (green), y=½x 2 (purple), y=2x 2 (red), and y=4x 2 (black) on the same axes For all these positive values of a , the graph still opens up Notice when 0< a 1, the graph appears toIs the graph symmetric with respect to the x axis?
Where the curve of x^2 4x 5 = 0 intercepts the yaxis, x = 0 Here we see that (4)^2 < 4*a*c, the curve does not intersect the xaxis The yintercept is (0, 5) We need to find y and xSolution for y = x^2 4x 45 What are the intercepts?Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
Y=x^21 (Graph Example), 4x2=2 (x6) (Solve Example) Algebra Calculator is a calculator that gives stepbystep help on algebra problems See More Examples » x3=5 1/3 1/4 y=x^21 Disclaimer This calculator is not perfect Please use at your own risk, and please alert us if something isn't working Thank youGraph of y=4x Below you can find the full step by step solution for you problem We hope it will be very helpful for you and it will help you to understand the solving process If it's not what You are looking for, type in into the box below your own function and let us find the graph of it The graph of y=4x represents a graph of a linearGraph the equation and Identify the x and yintercepts 4x5=9 Part 1 of 2 Graph 4x 5=9 7 6 5 Х 4 3 2 1




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Algebra Graph y=x^24x5 y = x2 4x − 5 y = x 2 4 x 5 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 4 x − 5 x 2 4 x 5In the graph of y = sin(x 2) the sine curve has translated to the right two units These translations are often referred to as horizontal or phase shifts Parameter c represents a phase shift (also called midline shifts) Now, lets graph y = 3 sin(4x 1) We will have to perform an amplitude and period change, in addition to a phase shift 4x2=x5 subtract 2 from both sides 4x=x3 subtract x from both sides 3x=3 divide both sides by 3 x=1, which makes y=x5 become y=15=6, so the solution to the system of equations is the point (1,6) The only graph containing this point is the top one on the first page




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Graph the parabola, y =x^21 by finding the turning point and using a table to find values for x and yAnswer (1 of 2) How do I draw the graph of y=3x^2 4x5?Use the process of completing the square to put it in vertex form y = 3x² 4x 5 y = 3(x² 4/3 ) 5 3 What fills in the ?



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Answer (1 of 11) Graphical Solution ANSWER These curves have very practical uses but it takes time for them to become friends for you Note the crossing of the y axis and the 5 constant term in the equation in this form Completing the square gives you the coordinates of the vertex SolvinCorrect answers 3 question Please graph the equations below using a table 1 y=x 7 2 y= 3x 4 3 y= 1/4x 2 4 y = 52x 5 y = 2/3x 2 please show your work and if you can't make the graph at least show your numbersY 34x 2 y 3 x 2 y 3x 2 graph y 3x 25 y 3x 22 y 3x 26 y 3x 26x4 y 3x 2yx 14 y 3x 2 answer y 3x 2 axis of symmetry y 3x 24 y 3x 22




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Given the parabola with standard equation {eq}y=x^24x5 {/eq} Then {eq}a=1, b=4, c=5 {/eq} Find the vertex using the vertex formula {eq}\begin{align} h&=\dfrac(e) Below is the graph of z = x2 y2 On the graph of the surface, sketch the traces that you found in parts (a) and (c) For problems 1213, nd an equation of the trace of the surface in the indicated plane Describe the graph of the trace 12 Surface 8x 2 y z2 = 9;{(1/2)(4/3)}² = 4/9 y = 3(x² 4/3 4/9) 5 3(4/9) y = 3(x 2/3)² 19/3 The vertex is at (



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Solution for The polynomial y = (x 5)(x – 2)(4x 3) has been graphed incorrectly Identify the error and how to fix the graph 125 100 75 50 25 3 21 1 2 31 y = x^2 4x 5 = x^2 4x 4 4 5 = (x^2 4x 4) 4 5 y = (x2)^2 9 Here, the vertex is at (2, 9) 2 x = 2 (the vertical line that goes through the vertex) 3 The graph of this function is called a parabola To graph a parabola, use its vertex (in this case, (2, 9) ) and yintercept (y = 5) The yintercept is the constant inDivide 4, the coefficient of the x term, by 2 to get 2 Then add the square of 2 to both sides of the equation This step makes the left hand side of the equation a perfect square Square 2 Add y1 to 4 Factor x^ {2}4x4 In general, when x^ {2}bxc is a perfect square, it can always be factored as \left (x\frac {b} {2}\right)^ {2}




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In this math video lesson I show how to graph y=(1/5)x4 The equation in this video is in slopeintercept form, y=mxb, and is a common way to graph an equ Graph the equation y=x^24x5 on the accompanying set of axes You must plot 5 points including the roots and the vertex Using the graph, determine the vertex of the parabola Answers 1 Show answers Another question on Mathematics Mathematics, 1640 Te and given the triangle below, find the ratio of the middle side length to thePlane z = 1 The trace in the z = 1 plane is the ellipse x2 y2 8 = 1




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Answer Option (3) is correct (2,4) belongs to y ≥ 4x 5 Stepbystep explanation Given the point (2,4) We have to find the equation of graph to which the point (2,4) belongsUse this graph of the quadratic function y=x^24x5 to solve the equation x^24x5=0 This graph shows a portion of an even function Use the graph to complete the table of values x f(Graph y=x^24x5 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabola




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Let us start with a function, in this case it is f(x) = x 2, but it could be anything f(x) = x 2 Here are some simple things we can do to move or scale it on the graph We can move it up or down by adding a constant to the yvalue g(x) = x 2 C Note to move the line down, we use a negative value for C C > 0 moves it up;Which statements about the graph of the function f(x) = x2 4x 2 are true?Precalculus questions and answers;



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Let y = f(x) be the continuous function that satisfies the equation x^45x^2y^24y^4=0 and whose graph contains the points (2, 1) and (2, 2) Let l be the line tangent to the graph of f at x = 2 aIf it's not what You are looking for, type in into the box below your own function and let us find the graph of it The graph of y^2=4x represents a graph of a quadratic function On the given graph you can find all of the important points for function y^2=4x (if they exist)The graph of y = f(x) will have at most one horizontal asymptote It is found according to the following 1 If m > n (that is, the degree of the denominator is larger than the degree of the numerator), then the graph of y = f(x) will have a horizontal asymptote at y = 0 (ie, the xaxis) 2



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The line equation is 4x y = 5 Write the equation in slopeintercept form y = mx b, where m is slope and b is yintercept y = 4x 5 Compare the equation with slope intercept form y = mx b slope = 4 and y intercept is 5 y intercept is 5, so the line crosses the y axis at (0, 5) Using slope find the next pointWhat is the minimum value for graph y = x^2 4x 5?Even and odd functions Even and odd are terms used to describe the symmetry of a function An even function is symmetric about the yaxis of a graph An odd function is symmetric about the origin (0,0) of a graphThis means that if you rotate an odd function 180° around the origin, you will have the same function you started with Most functions will be neither even nor odd




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Which of the following statements best describes the graph of 4x y = 1?Using the graph, what are the solution(s) to the equation x^24x5=0 Does this function have a maximum or a mini Algebra > Humanandalgebraiclanguage > SOLUTION Please help Use the graph of y=x^24x5 to answer the followingShow What You Know Week 18 Name_____ Date_____ Grade_____ ° Graph y = (4 – x)(x 2) ° Simplify (x 2)(3x – 3) ° Solve for x 2(4x 12) 4x = 12 ° Rotate 270 clockwise about the origin Write the new points and graph K E A H ° Create the following transformations in composition




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Zeros (–4,0), (8,0) yintercept (0,32) is the vertex, zero(s) and yintercept of the graph of y=x^2 4x 32C < 0 moves it down Given the function ƒ(x) = x 2 4x 5 Identify the zeros using factorization Draw a graph of the function Its vertex is at (2, 9)




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Minimum of a Quadratic Function The minimum of a quadratic function depends on the sign ofClick here👆to get an answer to your question ️ Plot a graph for the equation y = x^2 4x Join / Login Question Plot a graph for the equation y = x 2 Find the vertex of the following quadratic equation and plot the graph y = x 2Plot an Equation where x and y are related somehow, such as 2x 3y = 5 Description All Functions Enter an Equation using the variables x and/or y and an = , press Go




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To find the y coordinate, substitute the value of x = 1 in the original equation, y = 2x 2 4x 3 y = 2( 1) 2 4(1) 3 y = 2 4 3 = 7 2 y = 5 The vertex is ( 1, 5) Determine whether the function has maximum or minimum value The value of a = 2 < 0 (negative), so the graph of function opens downward and has a(a) Find the slope of the tangent to the curve $ y = 3 4x^2 2x^3 $ at the point where $ x = a $ (b) Find equations of the tangent lines at the points $ (1, 5) $ and $ (2, 3) $ (c) Graph the curve and both tangents on a common screenFind the area under the graph of y = x^2 4x, above the xaxis and between the vertical lines x = 1 and x = 5 Find the area under the graph of y = 1/x^2, above the xaxis and between the vertical lines x = 2 and x = 4 Get more help from Chegg Solve it




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